How far is Oxford House from Sandy Lake?
The distance between Sandy Lake (Sandy Lake Airport) and Oxford House (Oxford House Airport) is 151 miles / 244 kilometers / 132 nautical miles.
Sandy Lake Airport – Oxford House Airport
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Distance from Sandy Lake to Oxford House
There are several ways to calculate the distance from Sandy Lake to Oxford House. Here are two standard methods:
Vincenty's formula (applied above)- 151.395 miles
- 243.646 kilometers
- 131.559 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 151.150 miles
- 243.253 kilometers
- 131.346 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Sandy Lake to Oxford House?
The estimated flight time from Sandy Lake Airport to Oxford House Airport is 47 minutes.
What is the time difference between Sandy Lake and Oxford House?
There is no time difference between Sandy Lake and Oxford House.
Flight carbon footprint between Sandy Lake Airport (ZSJ) and Oxford House Airport (YOH)
On average, flying from Sandy Lake to Oxford House generates about 47 kg of CO2 per passenger, and 47 kilograms equals 104 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path from Sandy Lake to Oxford House
See the map of the shortest flight path between Sandy Lake Airport (ZSJ) and Oxford House Airport (YOH).
Airport information
Origin | Sandy Lake Airport |
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City: | Sandy Lake |
Country: | Canada |
IATA Code: | ZSJ |
ICAO Code: | CZSJ |
Coordinates: | 53°3′51″N, 93°20′39″W |
Destination | Oxford House Airport |
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City: | Oxford House |
Country: | Canada |
IATA Code: | YOH |
ICAO Code: | CYOH |
Coordinates: | 54°55′59″N, 95°16′44″W |