How far is San Angelo, TX, from Sandy Lake?

The distance between Sandy Lake (Sandy Lake Airport) and San Angelo (San Angelo Regional Airport) is 1541 miles / 2479 kilometers / 1339 nautical miles.

Distance from Sandy Lake to San Angelo

There are several ways to calculate the distance from Sandy Lake to San Angelo. Here are two standard methods:

Vincenty's formula (applied above)

• 1540.635 miles
• 2479.412 kilometers
• 1338.775 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula

• 1541.944 miles
• 2481.518 kilometers
• 1339.912 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Sandy Lake to San Angelo?

The estimated flight time from Sandy Lake Airport to San Angelo Regional Airport is 3 hours and 25 minutes.

What is the time difference between Sandy Lake and San Angelo?

There is no time difference between Sandy Lake and San Angelo.

Flight carbon footprint between Sandy Lake Airport (ZSJ) and San Angelo Regional Airport (SJT)

On average, flying from Sandy Lake to San Angelo generates about 182 kg of CO2 per passenger, and 182 kilograms equals 401 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Sandy Lake to San Angelo

See the map of the shortest flight path between Sandy Lake Airport (ZSJ) and San Angelo Regional Airport (SJT).

Airport information

Origin	Sandy Lake Airport
City:	Sandy Lake
Country:	Canada
IATA Code:	ZSJ
ICAO Code:	CZSJ
Coordinates:	53°3′51″N, 93°20′39″W

Destination	San Angelo Regional Airport
City:	San Angelo, TX
Country:	United States
IATA Code:	SJT
ICAO Code:	KSJT
Coordinates:	31°21′27″N, 100°29′45″W