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How far is Petersburg, AK, from Sandy Lake?

The distance between Sandy Lake (Sandy Lake Airport) and Petersburg (Petersburg James A. Johnson Airport) is 1575 miles / 2535 kilometers / 1369 nautical miles.

Sandy Lake Airport – Petersburg James A. Johnson Airport

Distance arrow
1575
Miles
Distance arrow
2535
Kilometers
Distance arrow
1369
Nautical miles

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Distance from Sandy Lake to Petersburg

There are several ways to calculate the distance from Sandy Lake to Petersburg. Here are two standard methods:

Vincenty's formula (applied above)
  • 1575.404 miles
  • 2535.367 kilometers
  • 1368.989 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 1570.209 miles
  • 2527.006 kilometers
  • 1364.474 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Sandy Lake to Petersburg?

The estimated flight time from Sandy Lake Airport to Petersburg James A. Johnson Airport is 3 hours and 28 minutes.

Flight carbon footprint between Sandy Lake Airport (ZSJ) and Petersburg James A. Johnson Airport (PSG)

On average, flying from Sandy Lake to Petersburg generates about 184 kg of CO2 per passenger, and 184 kilograms equals 406 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Sandy Lake to Petersburg

See the map of the shortest flight path between Sandy Lake Airport (ZSJ) and Petersburg James A. Johnson Airport (PSG).

Airport information

Origin Sandy Lake Airport
City: Sandy Lake
Country: Canada Flag of Canada
IATA Code: ZSJ
ICAO Code: CZSJ
Coordinates: 53°3′51″N, 93°20′39″W
Destination Petersburg James A. Johnson Airport
City: Petersburg, AK
Country: United States Flag of United States
IATA Code: PSG
ICAO Code: PAPG
Coordinates: 56°48′6″N, 132°56′42″W