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How far is Jacksonville, NC, from Sandy Lake?

The distance between Sandy Lake (Sandy Lake Airport) and Jacksonville (Albert J Ellis Airport) is 1476 miles / 2376 kilometers / 1283 nautical miles.

Sandy Lake Airport – Albert J Ellis Airport

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1476
Miles
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2376
Kilometers
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1283
Nautical miles

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Distance from Sandy Lake to Jacksonville

There are several ways to calculate the distance from Sandy Lake to Jacksonville. Here are two standard methods:

Vincenty's formula (applied above)
  • 1476.198 miles
  • 2375.710 kilometers
  • 1282.781 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 1475.918 miles
  • 2375.260 kilometers
  • 1282.538 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Sandy Lake to Jacksonville?

The estimated flight time from Sandy Lake Airport to Albert J Ellis Airport is 3 hours and 17 minutes.

Flight carbon footprint between Sandy Lake Airport (ZSJ) and Albert J Ellis Airport (OAJ)

On average, flying from Sandy Lake to Jacksonville generates about 178 kg of CO2 per passenger, and 178 kilograms equals 392 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Sandy Lake to Jacksonville

See the map of the shortest flight path between Sandy Lake Airport (ZSJ) and Albert J Ellis Airport (OAJ).

Airport information

Origin Sandy Lake Airport
City: Sandy Lake
Country: Canada Flag of Canada
IATA Code: ZSJ
ICAO Code: CZSJ
Coordinates: 53°3′51″N, 93°20′39″W
Destination Albert J Ellis Airport
City: Jacksonville, NC
Country: United States Flag of United States
IATA Code: OAJ
ICAO Code: KOAJ
Coordinates: 34°49′45″N, 77°36′43″W