How far is Wilmington, NC, from Sandy Lake?
The distance between Sandy Lake (Sandy Lake Airport) and Wilmington (Wilmington International Airport) is 1503 miles / 2420 kilometers / 1306 nautical miles.
Sandy Lake Airport – Wilmington International Airport
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Distance from Sandy Lake to Wilmington
There are several ways to calculate the distance from Sandy Lake to Wilmington. Here are two standard methods:
Vincenty's formula (applied above)- 1503.456 miles
- 2419.578 kilometers
- 1306.468 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 1503.322 miles
- 2419.363 kilometers
- 1306.351 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Sandy Lake to Wilmington?
The estimated flight time from Sandy Lake Airport to Wilmington International Airport is 3 hours and 20 minutes.
What is the time difference between Sandy Lake and Wilmington?
Flight carbon footprint between Sandy Lake Airport (ZSJ) and Wilmington International Airport (ILM)
On average, flying from Sandy Lake to Wilmington generates about 180 kg of CO2 per passenger, and 180 kilograms equals 396 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path from Sandy Lake to Wilmington
See the map of the shortest flight path between Sandy Lake Airport (ZSJ) and Wilmington International Airport (ILM).
Airport information
| Origin | Sandy Lake Airport |
|---|---|
| City: | Sandy Lake |
| Country: | Canada  |
| IATA Code: | ZSJ |
| ICAO Code: | CZSJ |
| Coordinates: | 53°3′51″N, 93°20′39″W |
| Destination | Wilmington International Airport |
|---|---|
| City: | Wilmington, NC |
| Country: | United States  |
| IATA Code: | ILM |
| ICAO Code: | KILM |
| Coordinates: | 34°16′14″N, 77°54′9″W |