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How far is Columbus, OH, from Sandy Lake?

The distance between Sandy Lake (Sandy Lake Airport) and Columbus (John Glenn Columbus International Airport) is 1028 miles / 1655 kilometers / 894 nautical miles.

Sandy Lake Airport – John Glenn Columbus International Airport

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1028
Miles
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1655
Kilometers
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894
Nautical miles

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Distance from Sandy Lake to Columbus

There are several ways to calculate the distance from Sandy Lake to Columbus. Here are two standard methods:

Vincenty's formula (applied above)
  • 1028.476 miles
  • 1655.172 kilometers
  • 893.721 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 1028.039 miles
  • 1654.469 kilometers
  • 893.342 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Sandy Lake to Columbus?

The estimated flight time from Sandy Lake Airport to John Glenn Columbus International Airport is 2 hours and 26 minutes.

Flight carbon footprint between Sandy Lake Airport (ZSJ) and John Glenn Columbus International Airport (CMH)

On average, flying from Sandy Lake to Columbus generates about 153 kg of CO2 per passenger, and 153 kilograms equals 336 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Sandy Lake to Columbus

See the map of the shortest flight path between Sandy Lake Airport (ZSJ) and John Glenn Columbus International Airport (CMH).

Airport information

Origin Sandy Lake Airport
City: Sandy Lake
Country: Canada Flag of Canada
IATA Code: ZSJ
ICAO Code: CZSJ
Coordinates: 53°3′51″N, 93°20′39″W
Destination John Glenn Columbus International Airport
City: Columbus, OH
Country: United States Flag of United States
IATA Code: CMH
ICAO Code: KCMH
Coordinates: 39°59′52″N, 82°53′30″W