How far is Cleveland, OH, from Sandy Lake?

The distance between Sandy Lake (Sandy Lake Airport) and Cleveland (Cleveland Hopkins International Airport) is 967 miles / 1556 kilometers / 840 nautical miles.

Distance from Sandy Lake to Cleveland

There are several ways to calculate the distance from Sandy Lake to Cleveland. Here are two standard methods:

Vincenty's formula (applied above)

• 967.136 miles
• 1556.455 kilometers
• 840.418 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula

• 966.393 miles
• 1555.259 kilometers
• 839.772 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Sandy Lake to Cleveland?

The estimated flight time from Sandy Lake Airport to Cleveland Hopkins International Airport is 2 hours and 19 minutes.

What is the time difference between Sandy Lake and Cleveland?

The time difference between Sandy Lake and Cleveland is 1 hour. Cleveland is 1 hour ahead of Sandy Lake.

Flight carbon footprint between Sandy Lake Airport (ZSJ) and Cleveland Hopkins International Airport (CLE)

On average, flying from Sandy Lake to Cleveland generates about 149 kg of CO2 per passenger, and 149 kilograms equals 328 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Sandy Lake to Cleveland

See the map of the shortest flight path between Sandy Lake Airport (ZSJ) and Cleveland Hopkins International Airport (CLE).

Airport information

Origin	Sandy Lake Airport
City:	Sandy Lake
Country:	Canada
IATA Code:	ZSJ
ICAO Code:	CZSJ
Coordinates:	53°3′51″N, 93°20′39″W

Destination	Cleveland Hopkins International Airport
City:	Cleveland, OH
Country:	United States
IATA Code:	CLE
ICAO Code:	KCLE
Coordinates:	41°24′42″N, 81°50′59″W