How far is Clarksburg, WV, from Sandy Lake?

The distance between Sandy Lake (Sandy Lake Airport) and Clarksburg (North Central West Virginia Airport) is 1136 miles / 1829 kilometers / 987 nautical miles.

Distance from Sandy Lake to Clarksburg

There are several ways to calculate the distance from Sandy Lake to Clarksburg. Here are two standard methods:

Vincenty's formula (applied above)

• 1136.290 miles
• 1828.682 kilometers
• 987.409 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula

• 1135.613 miles
• 1827.592 kilometers
• 986.821 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Sandy Lake to Clarksburg?

The estimated flight time from Sandy Lake Airport to North Central West Virginia Airport is 2 hours and 39 minutes.

What is the time difference between Sandy Lake and Clarksburg?

The time difference between Sandy Lake and Clarksburg is 1 hour. Clarksburg is 1 hour ahead of Sandy Lake.

Flight carbon footprint between Sandy Lake Airport (ZSJ) and North Central West Virginia Airport (CKB)

On average, flying from Sandy Lake to Clarksburg generates about 159 kg of CO2 per passenger, and 159 kilograms equals 350 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Sandy Lake to Clarksburg

See the map of the shortest flight path between Sandy Lake Airport (ZSJ) and North Central West Virginia Airport (CKB).

Airport information

Origin	Sandy Lake Airport
City:	Sandy Lake
Country:	Canada
IATA Code:	ZSJ
ICAO Code:	CZSJ
Coordinates:	53°3′51″N, 93°20′39″W

Destination	North Central West Virginia Airport
City:	Clarksburg, WV
Country:	United States
IATA Code:	CKB
ICAO Code:	KCKB
Coordinates:	39°17′47″N, 80°13′41″W