How far is Charlottesville, VA, from Sandy Lake?
The distance between Sandy Lake (Sandy Lake Airport) and Charlottesville (Charlottesville–Albemarle Airport) is 1253 miles / 2016 kilometers / 1089 nautical miles.
Sandy Lake Airport – Charlottesville–Albemarle Airport
Search flights
Distance from Sandy Lake to Charlottesville
There are several ways to calculate the distance from Sandy Lake to Charlottesville. Here are two standard methods:
Vincenty's formula (applied above)- 1252.968 miles
- 2016.456 kilometers
- 1088.799 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 1252.227 miles
- 2015.263 kilometers
- 1088.155 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Sandy Lake to Charlottesville?
The estimated flight time from Sandy Lake Airport to Charlottesville–Albemarle Airport is 2 hours and 52 minutes.
What is the time difference between Sandy Lake and Charlottesville?
Flight carbon footprint between Sandy Lake Airport (ZSJ) and Charlottesville–Albemarle Airport (CHO)
On average, flying from Sandy Lake to Charlottesville generates about 164 kg of CO2 per passenger, and 164 kilograms equals 361 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path from Sandy Lake to Charlottesville
See the map of the shortest flight path between Sandy Lake Airport (ZSJ) and Charlottesville–Albemarle Airport (CHO).
Airport information
Origin | Sandy Lake Airport |
---|---|
City: | Sandy Lake |
Country: | Canada |
IATA Code: | ZSJ |
ICAO Code: | CZSJ |
Coordinates: | 53°3′51″N, 93°20′39″W |
Destination | Charlottesville–Albemarle Airport |
---|---|
City: | Charlottesville, VA |
Country: | United States |
IATA Code: | CHO |
ICAO Code: | KCHO |
Coordinates: | 38°8′18″N, 78°27′10″W |