How far is Alamosa, CO, from Sandy Lake?

The distance between Sandy Lake (Sandy Lake Airport) and Alamosa (San Luis Valley Regional Airport) is 1236 miles / 1989 kilometers / 1074 nautical miles.

Distance from Sandy Lake to Alamosa

There are several ways to calculate the distance from Sandy Lake to Alamosa. Here are two standard methods:

Vincenty's formula (applied above)

• 1236.073 miles
• 1989.266 kilometers
• 1074.118 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula

• 1235.752 miles
• 1988.750 kilometers
• 1073.839 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Sandy Lake to Alamosa?

The estimated flight time from Sandy Lake Airport to San Luis Valley Regional Airport is 2 hours and 50 minutes.

What is the time difference between Sandy Lake and Alamosa?

The time difference between Sandy Lake and Alamosa is 1 hour. Alamosa is 1 hour behind Sandy Lake.

Flight carbon footprint between Sandy Lake Airport (ZSJ) and San Luis Valley Regional Airport (ALS)

On average, flying from Sandy Lake to Alamosa generates about 163 kg of CO2 per passenger, and 163 kilograms equals 359 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Sandy Lake to Alamosa

See the map of the shortest flight path between Sandy Lake Airport (ZSJ) and San Luis Valley Regional Airport (ALS).

Airport information

Origin	Sandy Lake Airport
City:	Sandy Lake
Country:	Canada
IATA Code:	ZSJ
ICAO Code:	CZSJ
Coordinates:	53°3′51″N, 93°20′39″W

Destination	San Luis Valley Regional Airport
City:	Alamosa, CO
Country:	United States
IATA Code:	ALS
ICAO Code:	KALS
Coordinates:	37°26′5″N, 105°52′1″W