How far is Sandy Lake from Temuco?

The distance between Temuco (La Araucanía International Airport) and Sandy Lake (Sandy Lake Airport) is 6453 miles / 10386 kilometers / 5608 nautical miles.

Distance from Temuco to Sandy Lake

There are several ways to calculate the distance from Temuco to Sandy Lake. Here are two standard methods:

Vincenty's formula (applied above)

• 6453.414 miles
• 10385.764 kilometers
• 5607.864 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula

• 6475.455 miles
• 10421.235 kilometers
• 5627.017 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Temuco to Sandy Lake?

The estimated flight time from La Araucanía International Airport to Sandy Lake Airport is 12 hours and 43 minutes.

What is the time difference between Temuco and Sandy Lake?

The time difference between Temuco and Sandy Lake is 3 hours. Sandy Lake is 3 hours behind Temuco.

Flight carbon footprint between La Araucanía International Airport (ZCO) and Sandy Lake Airport (ZSJ)

On average, flying from Temuco to Sandy Lake generates about 779 kg of CO2 per passenger, and 779 kilograms equals 1 717 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Temuco to Sandy Lake

See the map of the shortest flight path between La Araucanía International Airport (ZCO) and Sandy Lake Airport (ZSJ).

Airport information

Origin	La Araucanía International Airport
City:	Temuco
Country:	Chile
IATA Code:	ZCO
ICAO Code:	SCQP
Coordinates:	38°55′33″S, 72°39′5″W

Destination	Sandy Lake Airport
City:	Sandy Lake
Country:	Canada
IATA Code:	ZSJ
ICAO Code:	CZSJ
Coordinates:	53°3′51″N, 93°20′39″W