How far is Oxford House from Temuco?
The distance between Temuco (La Araucanía International Airport) and Oxford House (Oxford House Airport) is 6600 miles / 10622 kilometers / 5735 nautical miles.
La Araucanía International Airport – Oxford House Airport
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Distance from Temuco to Oxford House
There are several ways to calculate the distance from Temuco to Oxford House. Here are two standard methods:
Vincenty's formula (applied above)- 6599.943 miles
- 10621.578 kilometers
- 5735.194 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 6621.747 miles
- 10656.669 kilometers
- 5754.141 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Temuco to Oxford House?
The estimated flight time from La Araucanía International Airport to Oxford House Airport is 12 hours and 59 minutes.
What is the time difference between Temuco and Oxford House?
Flight carbon footprint between La Araucanía International Airport (ZCO) and Oxford House Airport (YOH)
On average, flying from Temuco to Oxford House generates about 799 kg of CO2 per passenger, and 799 kilograms equals 1 761 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path from Temuco to Oxford House
See the map of the shortest flight path between La Araucanía International Airport (ZCO) and Oxford House Airport (YOH).
Airport information
| Origin | La Araucanía International Airport |
|---|---|
| City: | Temuco |
| Country: | Chile  |
| IATA Code: | ZCO |
| ICAO Code: | SCQP |
| Coordinates: | 38°55′33″S, 72°39′5″W |
| Destination | Oxford House Airport |
|---|---|
| City: | Oxford House |
| Country: | Canada  |
| IATA Code: | YOH |
| ICAO Code: | CYOH |
| Coordinates: | 54°55′59″N, 95°16′44″W |