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How far is Poplar Hill from Temuco?

The distance between Temuco (La Araucanía International Airport) and Poplar Hill (Poplar Hill Airport) is 6401 miles / 10302 kilometers / 5562 nautical miles.

La Araucanía International Airport – Poplar Hill Airport

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6401
Miles
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10302
Kilometers
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5562
Nautical miles

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Distance from Temuco to Poplar Hill

There are several ways to calculate the distance from Temuco to Poplar Hill. Here are two standard methods:

Vincenty's formula (applied above)
  • 6401.164 miles
  • 10301.675 kilometers
  • 5562.459 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 6423.159 miles
  • 10337.073 kilometers
  • 5581.573 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Temuco to Poplar Hill?

The estimated flight time from La Araucanía International Airport to Poplar Hill Airport is 12 hours and 37 minutes.

Flight carbon footprint between La Araucanía International Airport (ZCO) and Poplar Hill Airport (YHP)

On average, flying from Temuco to Poplar Hill generates about 771 kg of CO2 per passenger, and 771 kilograms equals 1 701 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Temuco to Poplar Hill

See the map of the shortest flight path between La Araucanía International Airport (ZCO) and Poplar Hill Airport (YHP).

Airport information

Origin La Araucanía International Airport
City: Temuco
Country: Chile Flag of Chile
IATA Code: ZCO
ICAO Code: SCQP
Coordinates: 38°55′33″S, 72°39′5″W
Destination Poplar Hill Airport
City: Poplar Hill
Country: Canada Flag of Canada
IATA Code: YHP
ICAO Code: CPV7
Coordinates: 52°6′47″N, 94°15′20″W