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How far is Harrison, AR, from Temuco?

The distance between Temuco (La Araucanía International Airport) and Harrison (Boone County Airport) is 5336 miles / 8587 kilometers / 4637 nautical miles.

La Araucanía International Airport – Boone County Airport

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5336
Miles
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8587
Kilometers
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4637
Nautical miles

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Distance from Temuco to Harrison

There are several ways to calculate the distance from Temuco to Harrison. Here are two standard methods:

Vincenty's formula (applied above)
  • 5335.864 miles
  • 8587.241 kilometers
  • 4636.739 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 5356.842 miles
  • 8621.001 kilometers
  • 4654.968 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Temuco to Harrison?

The estimated flight time from La Araucanía International Airport to Boone County Airport is 10 hours and 36 minutes.

Flight carbon footprint between La Araucanía International Airport (ZCO) and Boone County Airport (HRO)

On average, flying from Temuco to Harrison generates about 628 kg of CO2 per passenger, and 628 kilograms equals 1 384 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Temuco to Harrison

See the map of the shortest flight path between La Araucanía International Airport (ZCO) and Boone County Airport (HRO).

Airport information

Origin La Araucanía International Airport
City: Temuco
Country: Chile Flag of Chile
IATA Code: ZCO
ICAO Code: SCQP
Coordinates: 38°55′33″S, 72°39′5″W
Destination Boone County Airport
City: Harrison, AR
Country: United States Flag of United States
IATA Code: HRO
ICAO Code: KHRO
Coordinates: 36°15′41″N, 93°9′16″W