How far is Sandy Lake from Zacatecas?

The distance between Zacatecas (Zacatecas International Airport) and Sandy Lake (Sandy Lake Airport) is 2138 miles / 3441 kilometers / 1858 nautical miles.

Distance from Zacatecas to Sandy Lake

There are several ways to calculate the distance from Zacatecas to Sandy Lake. Here are two standard methods:

Vincenty's formula (applied above)

• 2138.239 miles
• 3441.161 kilometers
• 1858.078 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula

• 2141.487 miles
• 3446.389 kilometers
• 1860.901 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Zacatecas to Sandy Lake?

The estimated flight time from Zacatecas International Airport to Sandy Lake Airport is 4 hours and 32 minutes.

What is the time difference between Zacatecas and Sandy Lake?

There is no time difference between Zacatecas and Sandy Lake.

Flight carbon footprint between Zacatecas International Airport (ZCL) and Sandy Lake Airport (ZSJ)

On average, flying from Zacatecas to Sandy Lake generates about 233 kg of CO2 per passenger, and 233 kilograms equals 514 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Zacatecas to Sandy Lake

See the map of the shortest flight path between Zacatecas International Airport (ZCL) and Sandy Lake Airport (ZSJ).

Airport information

Origin	Zacatecas International Airport
City:	Zacatecas
Country:	Mexico
IATA Code:	ZCL
ICAO Code:	MMZC
Coordinates:	22°53′49″N, 102°41′13″W

Destination	Sandy Lake Airport
City:	Sandy Lake
Country:	Canada
IATA Code:	ZSJ
ICAO Code:	CZSJ
Coordinates:	53°3′51″N, 93°20′39″W