How far is Sandy Lake from Oxford House?
The distance between Oxford House (Oxford House Airport) and Sandy Lake (Sandy Lake Airport) is 151 miles / 244 kilometers / 132 nautical miles.
Oxford House Airport – Sandy Lake Airport
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Distance from Oxford House to Sandy Lake
There are several ways to calculate the distance from Oxford House to Sandy Lake. Here are two standard methods:
Vincenty's formula (applied above)- 151.395 miles
- 243.646 kilometers
- 131.559 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 151.150 miles
- 243.253 kilometers
- 131.346 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Oxford House to Sandy Lake?
The estimated flight time from Oxford House Airport to Sandy Lake Airport is 47 minutes.
What is the time difference between Oxford House and Sandy Lake?
There is no time difference between Oxford House and Sandy Lake.
Flight carbon footprint between Oxford House Airport (YOH) and Sandy Lake Airport (ZSJ)
On average, flying from Oxford House to Sandy Lake generates about 47 kg of CO2 per passenger, and 47 kilograms equals 104 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path from Oxford House to Sandy Lake
See the map of the shortest flight path between Oxford House Airport (YOH) and Sandy Lake Airport (ZSJ).
Airport information
Origin | Oxford House Airport |
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City: | Oxford House |
Country: | Canada |
IATA Code: | YOH |
ICAO Code: | CYOH |
Coordinates: | 54°55′59″N, 95°16′44″W |
Destination | Sandy Lake Airport |
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City: | Sandy Lake |
Country: | Canada |
IATA Code: | ZSJ |
ICAO Code: | CZSJ |
Coordinates: | 53°3′51″N, 93°20′39″W |