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How far is Petersburg, AK, from Oxford House?

The distance between Oxford House (Oxford House Airport) and Petersburg (Petersburg James A. Johnson Airport) is 1452 miles / 2337 kilometers / 1262 nautical miles.

Oxford House Airport – Petersburg James A. Johnson Airport

Distance arrow
1452
Miles
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2337
Kilometers
Distance arrow
1262
Nautical miles

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Distance from Oxford House to Petersburg

There are several ways to calculate the distance from Oxford House to Petersburg. Here are two standard methods:

Vincenty's formula (applied above)
  • 1452.291 miles
  • 2337.236 kilometers
  • 1262.007 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 1447.363 miles
  • 2329.305 kilometers
  • 1257.724 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Oxford House to Petersburg?

The estimated flight time from Oxford House Airport to Petersburg James A. Johnson Airport is 3 hours and 14 minutes.

Flight carbon footprint between Oxford House Airport (YOH) and Petersburg James A. Johnson Airport (PSG)

On average, flying from Oxford House to Petersburg generates about 176 kg of CO2 per passenger, and 176 kilograms equals 389 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Oxford House to Petersburg

See the map of the shortest flight path between Oxford House Airport (YOH) and Petersburg James A. Johnson Airport (PSG).

Airport information

Origin Oxford House Airport
City: Oxford House
Country: Canada Flag of Canada
IATA Code: YOH
ICAO Code: CYOH
Coordinates: 54°55′59″N, 95°16′44″W
Destination Petersburg James A. Johnson Airport
City: Petersburg, AK
Country: United States Flag of United States
IATA Code: PSG
ICAO Code: PAPG
Coordinates: 56°48′6″N, 132°56′42″W