How far is Burlington, IA, from Oxford House?
The distance between Oxford House (Oxford House Airport) and Burlington (Southeast Iowa Regional Airport) is 996 miles / 1603 kilometers / 866 nautical miles.
Oxford House Airport – Southeast Iowa Regional Airport
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Distance from Oxford House to Burlington
There are several ways to calculate the distance from Oxford House to Burlington. Here are two standard methods:
Vincenty's formula (applied above)- 996.050 miles
- 1602.987 kilometers
- 865.544 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 996.012 miles
- 1602.926 kilometers
- 865.511 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Oxford House to Burlington?
The estimated flight time from Oxford House Airport to Southeast Iowa Regional Airport is 2 hours and 23 minutes.
What is the time difference between Oxford House and Burlington?
There is no time difference between Oxford House and Burlington.
Flight carbon footprint between Oxford House Airport (YOH) and Southeast Iowa Regional Airport (BRL)
On average, flying from Oxford House to Burlington generates about 151 kg of CO2 per passenger, and 151 kilograms equals 332 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path from Oxford House to Burlington
See the map of the shortest flight path between Oxford House Airport (YOH) and Southeast Iowa Regional Airport (BRL).
Airport information
Origin | Oxford House Airport |
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City: | Oxford House |
Country: | Canada |
IATA Code: | YOH |
ICAO Code: | CYOH |
Coordinates: | 54°55′59″N, 95°16′44″W |
Destination | Southeast Iowa Regional Airport |
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City: | Burlington, IA |
Country: | United States |
IATA Code: | BRL |
ICAO Code: | KBRL |
Coordinates: | 40°46′59″N, 91°7′31″W |