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How far is San Angelo, TX, from Yakutsk?

The distance between Yakutsk (Yakutsk Airport) and San Angelo (San Angelo Regional Airport) is 5416 miles / 8716 kilometers / 4706 nautical miles.

Yakutsk Airport – San Angelo Regional Airport

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5416
Miles
Distance arrow
8716
Kilometers
Distance arrow
4706
Nautical miles

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Distance from Yakutsk to San Angelo

There are several ways to calculate the distance from Yakutsk to San Angelo. Here are two standard methods:

Vincenty's formula (applied above)
  • 5415.754 miles
  • 8715.812 kilometers
  • 4706.162 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 5403.528 miles
  • 8696.136 kilometers
  • 4695.538 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Yakutsk to San Angelo?

The estimated flight time from Yakutsk Airport to San Angelo Regional Airport is 10 hours and 45 minutes.

Flight carbon footprint between Yakutsk Airport (YKS) and San Angelo Regional Airport (SJT)

On average, flying from Yakutsk to San Angelo generates about 638 kg of CO2 per passenger, and 638 kilograms equals 1 407 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Yakutsk to San Angelo

See the map of the shortest flight path between Yakutsk Airport (YKS) and San Angelo Regional Airport (SJT).

Airport information

Origin Yakutsk Airport
City: Yakutsk
Country: Russia Flag of Russia
IATA Code: YKS
ICAO Code: UEEE
Coordinates: 62°5′35″N, 129°46′15″E
Destination San Angelo Regional Airport
City: San Angelo, TX
Country: United States Flag of United States
IATA Code: SJT
ICAO Code: KSJT
Coordinates: 31°21′27″N, 100°29′45″W