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How far is Sandy Lake from Valencia?

The distance between Valencia (Arturo Michelena International Airport) and Sandy Lake (Sandy Lake Airport) is 3279 miles / 5276 kilometers / 2849 nautical miles.

Arturo Michelena International Airport – Sandy Lake Airport

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3279
Miles
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5276
Kilometers
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2849
Nautical miles

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Distance from Valencia to Sandy Lake

There are several ways to calculate the distance from Valencia to Sandy Lake. Here are two standard methods:

Vincenty's formula (applied above)
  • 3278.657 miles
  • 5276.487 kilometers
  • 2849.075 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 3284.454 miles
  • 5285.816 kilometers
  • 2854.112 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Valencia to Sandy Lake?

The estimated flight time from Arturo Michelena International Airport to Sandy Lake Airport is 6 hours and 42 minutes.

Flight carbon footprint between Arturo Michelena International Airport (VLN) and Sandy Lake Airport (ZSJ)

On average, flying from Valencia to Sandy Lake generates about 368 kg of CO2 per passenger, and 368 kilograms equals 811 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Valencia to Sandy Lake

See the map of the shortest flight path between Arturo Michelena International Airport (VLN) and Sandy Lake Airport (ZSJ).

Airport information

Origin Arturo Michelena International Airport
City: Valencia
Country: Venezuela Flag of Venezuela
IATA Code: VLN
ICAO Code: SVVA
Coordinates: 10°8′59″N, 67°55′42″W
Destination Sandy Lake Airport
City: Sandy Lake
Country: Canada Flag of Canada
IATA Code: ZSJ
ICAO Code: CZSJ
Coordinates: 53°3′51″N, 93°20′39″W