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How far is Sandy Lake from San Julian?

The distance between San Julian (Capitán José Daniel Vazquez Airport) and Sandy Lake (Sandy Lake Airport) is 7207 miles / 11598 kilometers / 6262 nautical miles.

Capitán José Daniel Vazquez Airport – Sandy Lake Airport

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7207
Miles
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11598
Kilometers
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6262
Nautical miles

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Distance from San Julian to Sandy Lake

There are several ways to calculate the distance from San Julian to Sandy Lake. Here are two standard methods:

Vincenty's formula (applied above)
  • 7206.735 miles
  • 11598.116 kilometers
  • 6262.481 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 7229.063 miles
  • 11634.049 kilometers
  • 6281.884 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from San Julian to Sandy Lake?

The estimated flight time from Capitán José Daniel Vazquez Airport to Sandy Lake Airport is 14 hours and 8 minutes.

Flight carbon footprint between Capitán José Daniel Vazquez Airport (ULA) and Sandy Lake Airport (ZSJ)

On average, flying from San Julian to Sandy Lake generates about 884 kg of CO2 per passenger, and 884 kilograms equals 1 949 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from San Julian to Sandy Lake

See the map of the shortest flight path between Capitán José Daniel Vazquez Airport (ULA) and Sandy Lake Airport (ZSJ).

Airport information

Origin Capitán José Daniel Vazquez Airport
City: San Julian
Country: Argentina Flag of Argentina
IATA Code: ULA
ICAO Code: SAWJ
Coordinates: 49°18′24″S, 67°48′9″W
Destination Sandy Lake Airport
City: Sandy Lake
Country: Canada Flag of Canada
IATA Code: ZSJ
ICAO Code: CZSJ
Coordinates: 53°3′51″N, 93°20′39″W