How far is Hughes, AK, from Tatitlek, AK?
The distance between Tatitlek (Tatitlek Airport) and Hughes (Hughes Airport (Alaska)) is 427 miles / 688 kilometers / 371 nautical miles.
The driving distance from Tatitlek (TEK) to Hughes (HUS) is 733 miles / 1179 kilometers, and travel time by car is about 39 hours 16 minutes.
Tatitlek Airport – Hughes Airport (Alaska)
Search flights
Distance from Tatitlek to Hughes
There are several ways to calculate the distance from Tatitlek to Hughes. Here are two standard methods:
Vincenty's formula (applied above)- 427.492 miles
- 687.981 kilometers
- 371.480 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 426.273 miles
- 686.020 kilometers
- 370.421 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Tatitlek to Hughes?
The estimated flight time from Tatitlek Airport to Hughes Airport (Alaska) is 1 hour and 18 minutes.
What is the time difference between Tatitlek and Hughes?
Flight carbon footprint between Tatitlek Airport (TEK) and Hughes Airport (Alaska) (HUS)
On average, flying from Tatitlek to Hughes generates about 88 kg of CO2 per passenger, and 88 kilograms equals 194 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path and driving directions from Tatitlek to Hughes
See the map of the shortest flight path between Tatitlek Airport (TEK) and Hughes Airport (Alaska) (HUS).
Airport information
Origin | Tatitlek Airport |
---|---|
City: | Tatitlek, AK |
Country: | United States |
IATA Code: | TEK |
ICAO Code: | PAKA |
Coordinates: | 60°52′17″N, 146°41′25″W |
Destination | Hughes Airport (Alaska) |
---|---|
City: | Hughes, AK |
Country: | United States |
IATA Code: | HUS |
ICAO Code: | PAHU |
Coordinates: | 66°2′27″N, 154°15′46″W |