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How far is Jacksonville, NC, from Kingstown?

The distance between Kingstown (Argyle International Airport) and Jacksonville (Albert J Ellis Airport) is 1813 miles / 2918 kilometers / 1575 nautical miles.

Argyle International Airport – Albert J Ellis Airport

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1813
Miles
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2918
Kilometers
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1575
Nautical miles

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Distance from Kingstown to Jacksonville

There are several ways to calculate the distance from Kingstown to Jacksonville. Here are two standard methods:

Vincenty's formula (applied above)
  • 1812.881 miles
  • 2917.548 kilometers
  • 1575.350 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 1816.644 miles
  • 2923.605 kilometers
  • 1578.621 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Kingstown to Jacksonville?

The estimated flight time from Argyle International Airport to Albert J Ellis Airport is 3 hours and 55 minutes.

Flight carbon footprint between Argyle International Airport (SVD) and Albert J Ellis Airport (OAJ)

On average, flying from Kingstown to Jacksonville generates about 201 kg of CO2 per passenger, and 201 kilograms equals 443 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Kingstown to Jacksonville

See the map of the shortest flight path between Argyle International Airport (SVD) and Albert J Ellis Airport (OAJ).

Airport information

Origin Argyle International Airport
City: Kingstown
Country: Saint Vincent and the Grenadines Flag of Saint Vincent and the Grenadines
IATA Code: SVD
ICAO Code: TVSA
Coordinates: 13°9′24″N, 61°8′59″W
Destination Albert J Ellis Airport
City: Jacksonville, NC
Country: United States Flag of United States
IATA Code: OAJ
ICAO Code: KOAJ
Coordinates: 34°49′45″N, 77°36′43″W