How far is Windsor from Sialkot?
The distance between Sialkot (Sialkot International Airport) and Windsor (Windsor International Airport) is 7086 miles / 11404 kilometers / 6158 nautical miles.
Sialkot International Airport – Windsor International Airport
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Distance from Sialkot to Windsor
There are several ways to calculate the distance from Sialkot to Windsor. Here are two standard methods:
Vincenty's formula (applied above)- 7085.983 miles
- 11403.784 kilometers
- 6157.551 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 7071.225 miles
- 11380.033 kilometers
- 6144.726 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Sialkot to Windsor?
The estimated flight time from Sialkot International Airport to Windsor International Airport is 13 hours and 54 minutes.
What is the time difference between Sialkot and Windsor?
The time difference between Sialkot and Windsor is 10 hours. Windsor is 10 hours behind Sialkot.
Flight carbon footprint between Sialkot International Airport (SKT) and Windsor International Airport (YQG)
On average, flying from Sialkot to Windsor generates about 867 kg of CO2 per passenger, and 867 kilograms equals 1 911 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path from Sialkot to Windsor
See the map of the shortest flight path between Sialkot International Airport (SKT) and Windsor International Airport (YQG).
Airport information
Origin | Sialkot International Airport |
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City: | Sialkot |
Country: | Pakistan |
IATA Code: | SKT |
ICAO Code: | OPST |
Coordinates: | 32°32′8″N, 74°21′50″E |
Destination | Windsor International Airport |
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City: | Windsor |
Country: | Canada |
IATA Code: | YQG |
ICAO Code: | CYQG |
Coordinates: | 42°16′32″N, 82°57′20″W |