How far is Sandy Lake from San Angelo, TX?

The distance between San Angelo (San Angelo Regional Airport) and Sandy Lake (Sandy Lake Airport) is 1541 miles / 2479 kilometers / 1339 nautical miles.

Distance from San Angelo to Sandy Lake

There are several ways to calculate the distance from San Angelo to Sandy Lake. Here are two standard methods:

Vincenty's formula (applied above)

• 1540.635 miles
• 2479.412 kilometers
• 1338.775 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula

• 1541.944 miles
• 2481.518 kilometers
• 1339.912 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from San Angelo to Sandy Lake?

The estimated flight time from San Angelo Regional Airport to Sandy Lake Airport is 3 hours and 25 minutes.

What is the time difference between San Angelo and Sandy Lake?

There is no time difference between San Angelo and Sandy Lake.

Flight carbon footprint between San Angelo Regional Airport (SJT) and Sandy Lake Airport (ZSJ)

On average, flying from San Angelo to Sandy Lake generates about 182 kg of CO2 per passenger, and 182 kilograms equals 401 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from San Angelo to Sandy Lake

See the map of the shortest flight path between San Angelo Regional Airport (SJT) and Sandy Lake Airport (ZSJ).

Airport information

Origin	San Angelo Regional Airport
City:	San Angelo, TX
Country:	United States
IATA Code:	SJT
ICAO Code:	KSJT
Coordinates:	31°21′27″N, 100°29′45″W

Destination	Sandy Lake Airport
City:	Sandy Lake
Country:	Canada
IATA Code:	ZSJ
ICAO Code:	CZSJ
Coordinates:	53°3′51″N, 93°20′39″W