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How far is Sandy Lake from Rotterdam?

The distance between Rotterdam (Rotterdam The Hague Airport) and Sandy Lake (Sandy Lake Airport) is 3784 miles / 6090 kilometers / 3288 nautical miles.

Rotterdam The Hague Airport – Sandy Lake Airport

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3784
Miles
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6090
Kilometers
Distance arrow
3288
Nautical miles

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Distance from Rotterdam to Sandy Lake

There are several ways to calculate the distance from Rotterdam to Sandy Lake. Here are two standard methods:

Vincenty's formula (applied above)
  • 3784.281 miles
  • 6090.210 kilometers
  • 3288.450 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 3772.149 miles
  • 6070.685 kilometers
  • 3277.908 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Rotterdam to Sandy Lake?

The estimated flight time from Rotterdam The Hague Airport to Sandy Lake Airport is 7 hours and 39 minutes.

Flight carbon footprint between Rotterdam The Hague Airport (RTM) and Sandy Lake Airport (ZSJ)

On average, flying from Rotterdam to Sandy Lake generates about 430 kg of CO2 per passenger, and 430 kilograms equals 947 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Rotterdam to Sandy Lake

See the map of the shortest flight path between Rotterdam The Hague Airport (RTM) and Sandy Lake Airport (ZSJ).

Airport information

Origin Rotterdam The Hague Airport
City: Rotterdam
Country: Netherlands Flag of Netherlands
IATA Code: RTM
ICAO Code: EHRD
Coordinates: 51°57′24″N, 4°26′13″E
Destination Sandy Lake Airport
City: Sandy Lake
Country: Canada Flag of Canada
IATA Code: ZSJ
ICAO Code: CZSJ
Coordinates: 53°3′51″N, 93°20′39″W