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How far is Oxford House from Petropavlovsk-Kamchatsky?

The distance between Petropavlovsk-Kamchatsky (Elizovo Airport) and Oxford House (Oxford House Airport) is 3885 miles / 6252 kilometers / 3376 nautical miles.

Elizovo Airport – Oxford House Airport

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3885
Miles
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6252
Kilometers
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3376
Nautical miles

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Distance from Petropavlovsk-Kamchatsky to Oxford House

There are several ways to calculate the distance from Petropavlovsk-Kamchatsky to Oxford House. Here are two standard methods:

Vincenty's formula (applied above)
  • 3884.667 miles
  • 6251.766 kilometers
  • 3375.684 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 3871.895 miles
  • 6231.211 kilometers
  • 3364.585 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Petropavlovsk-Kamchatsky to Oxford House?

The estimated flight time from Elizovo Airport to Oxford House Airport is 7 hours and 51 minutes.

Flight carbon footprint between Elizovo Airport (PKC) and Oxford House Airport (YOH)

On average, flying from Petropavlovsk-Kamchatsky to Oxford House generates about 442 kg of CO2 per passenger, and 442 kilograms equals 974 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Petropavlovsk-Kamchatsky to Oxford House

See the map of the shortest flight path between Elizovo Airport (PKC) and Oxford House Airport (YOH).

Airport information

Origin Elizovo Airport
City: Petropavlovsk-Kamchatsky
Country: Russia Flag of Russia
IATA Code: PKC
ICAO Code: UHPP
Coordinates: 53°10′4″N, 158°27′14″E
Destination Oxford House Airport
City: Oxford House
Country: Canada Flag of Canada
IATA Code: YOH
ICAO Code: CYOH
Coordinates: 54°55′59″N, 95°16′44″W