How far is Monroe, LA, from Paducah, KY?
The distance between Paducah (Barkley Regional Airport) and Monroe (Monroe Regional Airport) is 364 miles / 586 kilometers / 317 nautical miles.
The driving distance from Paducah (PAH) to Monroe (MLU) is 434 miles / 699 kilometers, and travel time by car is about 8 hours 55 minutes.
Barkley Regional Airport – Monroe Regional Airport
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Distance from Paducah to Monroe
There are several ways to calculate the distance from Paducah to Monroe. Here are two standard methods:
Vincenty's formula (applied above)- 364.386 miles
- 586.422 kilometers
- 316.642 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 364.806 miles
- 587.099 kilometers
- 317.008 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Paducah to Monroe?
The estimated flight time from Barkley Regional Airport to Monroe Regional Airport is 1 hour and 11 minutes.
What is the time difference between Paducah and Monroe?
Flight carbon footprint between Barkley Regional Airport (PAH) and Monroe Regional Airport (MLU)
On average, flying from Paducah to Monroe generates about 79 kg of CO2 per passenger, and 79 kilograms equals 173 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path and driving directions from Paducah to Monroe
See the map of the shortest flight path between Barkley Regional Airport (PAH) and Monroe Regional Airport (MLU).
Airport information
Origin | Barkley Regional Airport |
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City: | Paducah, KY |
Country: | United States |
IATA Code: | PAH |
ICAO Code: | KPAH |
Coordinates: | 37°3′38″N, 88°46′25″W |
Destination | Monroe Regional Airport |
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City: | Monroe, LA |
Country: | United States |
IATA Code: | MLU |
ICAO Code: | KMLU |
Coordinates: | 32°30′39″N, 92°2′15″W |