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How far is Arauca from Manicoré?

The distance between Manicoré (Manicoré Airport) and Arauca (Santiago Pérez Quiroz Airport) is 1100 miles / 1770 kilometers / 956 nautical miles.

The driving distance from Manicoré (MNX) to Arauca (AUC) is 2727 miles / 4389 kilometers, and travel time by car is about 145 hours 58 minutes.

Manicoré Airport – Santiago Pérez Quiroz Airport

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1100
Miles
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1770
Kilometers
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956
Nautical miles

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Distance from Manicoré to Arauca

There are several ways to calculate the distance from Manicoré to Arauca. Here are two standard methods:

Vincenty's formula (applied above)
  • 1099.752 miles
  • 1769.879 kilometers
  • 955.658 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 1103.286 miles
  • 1775.567 kilometers
  • 958.729 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Manicoré to Arauca?

The estimated flight time from Manicoré Airport to Santiago Pérez Quiroz Airport is 2 hours and 34 minutes.

Flight carbon footprint between Manicoré Airport (MNX) and Santiago Pérez Quiroz Airport (AUC)

On average, flying from Manicoré to Arauca generates about 157 kg of CO2 per passenger, and 157 kilograms equals 346 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path and driving directions from Manicoré to Arauca

See the map of the shortest flight path between Manicoré Airport (MNX) and Santiago Pérez Quiroz Airport (AUC).

Airport information

Origin Manicoré Airport
City: Manicoré
Country: Brazil Flag of Brazil
IATA Code: MNX
ICAO Code: SBMY
Coordinates: 5°48′40″S, 61°16′41″W
Destination Santiago Pérez Quiroz Airport
City: Arauca
Country: Colombia Flag of Colombia
IATA Code: AUC
ICAO Code: SKUC
Coordinates: 7°4′7″N, 70°44′12″W