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How far is Sandy Lake from Lukla?

The distance between Lukla (Tenzing–Hillary Airport) and Sandy Lake (Sandy Lake Airport) is 6871 miles / 11058 kilometers / 5971 nautical miles.

Tenzing–Hillary Airport – Sandy Lake Airport

Distance arrow
6871
Miles
Distance arrow
11058
Kilometers
Distance arrow
5971
Nautical miles
Flight time duration
13 h 30 min
Time Difference
11 h 45 min
CO2 emission
837 kg

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Distance from Lukla to Sandy Lake

There are several ways to calculate the distance from Lukla to Sandy Lake. Here are two standard methods:

Vincenty's formula (applied above)
  • 6871.383 miles
  • 11058.419 kilometers
  • 5971.068 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 6857.444 miles
  • 11035.986 kilometers
  • 5958.956 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Lukla to Sandy Lake?

The estimated flight time from Tenzing–Hillary Airport to Sandy Lake Airport is 13 hours and 30 minutes.

Flight carbon footprint between Tenzing–Hillary Airport (LUA) and Sandy Lake Airport (ZSJ)

On average, flying from Lukla to Sandy Lake generates about 837 kg of CO2 per passenger, and 837 kilograms equals 1 845 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Lukla to Sandy Lake

See the map of the shortest flight path between Tenzing–Hillary Airport (LUA) and Sandy Lake Airport (ZSJ).

Airport information

Origin Tenzing–Hillary Airport
City: Lukla
Country: Nepal Flag of Nepal
IATA Code: LUA
ICAO Code: VNLK
Coordinates: 27°41′12″N, 86°43′46″E
Destination Sandy Lake Airport
City: Sandy Lake
Country: Canada Flag of Canada
IATA Code: ZSJ
ICAO Code: CZSJ
Coordinates: 53°3′51″N, 93°20′39″W