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How far is San Angelo, TX, from Milan?

The distance between Milan (Linate Airport) and San Angelo (San Angelo Regional Airport) is 5562 miles / 8951 kilometers / 4833 nautical miles.

Linate Airport – San Angelo Regional Airport

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5562
Miles
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8951
Kilometers
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4833
Nautical miles

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Distance from Milan to San Angelo

There are several ways to calculate the distance from Milan to San Angelo. Here are two standard methods:

Vincenty's formula (applied above)
  • 5561.910 miles
  • 8951.026 kilometers
  • 4833.167 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 5549.619 miles
  • 8931.245 kilometers
  • 4822.487 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Milan to San Angelo?

The estimated flight time from Linate Airport to San Angelo Regional Airport is 11 hours and 1 minutes.

Flight carbon footprint between Linate Airport (LIN) and San Angelo Regional Airport (SJT)

On average, flying from Milan to San Angelo generates about 658 kg of CO2 per passenger, and 658 kilograms equals 1 450 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Milan to San Angelo

See the map of the shortest flight path between Linate Airport (LIN) and San Angelo Regional Airport (SJT).

Airport information

Origin Linate Airport
City: Milan
Country: Italy Flag of Italy
IATA Code: LIN
ICAO Code: LIML
Coordinates: 45°26′42″N, 9°16′36″E
Destination San Angelo Regional Airport
City: San Angelo, TX
Country: United States Flag of United States
IATA Code: SJT
ICAO Code: KSJT
Coordinates: 31°21′27″N, 100°29′45″W