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How far is Sandy Lake from Xalapa?

The distance between Xalapa (El Lencero Airport) and Sandy Lake (Sandy Lake Airport) is 2324 miles / 3739 kilometers / 2019 nautical miles.

El Lencero Airport – Sandy Lake Airport

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2324
Miles
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3739
Kilometers
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2019
Nautical miles

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Distance from Xalapa to Sandy Lake

There are several ways to calculate the distance from Xalapa to Sandy Lake. Here are two standard methods:

Vincenty's formula (applied above)
  • 2323.563 miles
  • 3739.411 kilometers
  • 2019.121 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 2328.136 miles
  • 3746.772 kilometers
  • 2023.095 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Xalapa to Sandy Lake?

The estimated flight time from El Lencero Airport to Sandy Lake Airport is 4 hours and 53 minutes.

What is the time difference between Xalapa and Sandy Lake?

There is no time difference between Xalapa and Sandy Lake.

Flight carbon footprint between El Lencero Airport (JAL) and Sandy Lake Airport (ZSJ)

On average, flying from Xalapa to Sandy Lake generates about 255 kg of CO2 per passenger, and 255 kilograms equals 561 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Xalapa to Sandy Lake

See the map of the shortest flight path between El Lencero Airport (JAL) and Sandy Lake Airport (ZSJ).

Airport information

Origin El Lencero Airport
City: Xalapa
Country: Mexico Flag of Mexico
IATA Code: JAL
ICAO Code: MMJA
Coordinates: 19°28′30″N, 96°47′51″W
Destination Sandy Lake Airport
City: Sandy Lake
Country: Canada Flag of Canada
IATA Code: ZSJ
ICAO Code: CZSJ
Coordinates: 53°3′51″N, 93°20′39″W