How far is Anshan from Pathankot?
The distance between Pathankot (Pathankot Airport) and Anshan (Anshan Teng'ao Airport) is 2660 miles / 4280 kilometers / 2311 nautical miles.
The driving distance from Pathankot (IXP) to Anshan (AOG) is 4139 miles / 6661 kilometers, and travel time by car is about 77 hours 21 minutes.
Pathankot Airport – Anshan Teng'ao Airport
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Distance from Pathankot to Anshan
There are several ways to calculate the distance from Pathankot to Anshan. Here are two standard methods:
Vincenty's formula (applied above)- 2659.554 miles
- 4280.138 kilometers
- 2311.090 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 2654.031 miles
- 4271.248 kilometers
- 2306.290 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Pathankot to Anshan?
The estimated flight time from Pathankot Airport to Anshan Teng'ao Airport is 5 hours and 32 minutes.
What is the time difference between Pathankot and Anshan?
Flight carbon footprint between Pathankot Airport (IXP) and Anshan Teng'ao Airport (AOG)
On average, flying from Pathankot to Anshan generates about 294 kg of CO2 per passenger, and 294 kilograms equals 648 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path and driving directions from Pathankot to Anshan
See the map of the shortest flight path between Pathankot Airport (IXP) and Anshan Teng'ao Airport (AOG).
Airport information
| Origin | Pathankot Airport |
|---|---|
| City: | Pathankot |
| Country: | India  |
| IATA Code: | IXP |
| ICAO Code: | VIPK |
| Coordinates: | 32°14′0″N, 75°38′3″E |
| Destination | Anshan Teng'ao Airport |
|---|---|
| City: | Anshan |
| Country: | China  |
| IATA Code: | AOG |
| ICAO Code: | ZYAS |
| Coordinates: | 41°6′19″N, 122°51′14″E |