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How far is Sandy Lake from Wilmington, NC?

The distance between Wilmington (Wilmington International Airport) and Sandy Lake (Sandy Lake Airport) is 1503 miles / 2420 kilometers / 1306 nautical miles.

Wilmington International Airport – Sandy Lake Airport

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1503
Miles
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2420
Kilometers
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1306
Nautical miles

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Distance from Wilmington to Sandy Lake

There are several ways to calculate the distance from Wilmington to Sandy Lake. Here are two standard methods:

Vincenty's formula (applied above)
  • 1503.456 miles
  • 2419.578 kilometers
  • 1306.468 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 1503.322 miles
  • 2419.363 kilometers
  • 1306.351 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Wilmington to Sandy Lake?

The estimated flight time from Wilmington International Airport to Sandy Lake Airport is 3 hours and 20 minutes.

Flight carbon footprint between Wilmington International Airport (ILM) and Sandy Lake Airport (ZSJ)

On average, flying from Wilmington to Sandy Lake generates about 180 kg of CO2 per passenger, and 180 kilograms equals 396 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Wilmington to Sandy Lake

See the map of the shortest flight path between Wilmington International Airport (ILM) and Sandy Lake Airport (ZSJ).

Airport information

Origin Wilmington International Airport
City: Wilmington, NC
Country: United States Flag of United States
IATA Code: ILM
ICAO Code: KILM
Coordinates: 34°16′14″N, 77°54′9″W
Destination Sandy Lake Airport
City: Sandy Lake
Country: Canada Flag of Canada
IATA Code: ZSJ
ICAO Code: CZSJ
Coordinates: 53°3′51″N, 93°20′39″W