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How far is Manizales from Galapagos?

The distance between Galapagos (Seymour Airport) and Manizales (La Nubia Airport) is 1090 miles / 1754 kilometers / 947 nautical miles.

Seymour Airport – La Nubia Airport

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1090
Miles
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1754
Kilometers
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947
Nautical miles

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Distance from Galapagos to Manizales

There are several ways to calculate the distance from Galapagos to Manizales. Here are two standard methods:

Vincenty's formula (applied above)
  • 1089.801 miles
  • 1753.864 kilometers
  • 947.011 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 1089.452 miles
  • 1753.302 kilometers
  • 946.708 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Galapagos to Manizales?

The estimated flight time from Seymour Airport to La Nubia Airport is 2 hours and 33 minutes.

Flight carbon footprint between Seymour Airport (GPS) and La Nubia Airport (MZL)

On average, flying from Galapagos to Manizales generates about 156 kg of CO2 per passenger, and 156 kilograms equals 344 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Galapagos to Manizales

See the map of the shortest flight path between Seymour Airport (GPS) and La Nubia Airport (MZL).

Airport information

Origin Seymour Airport
City: Galapagos
Country: Ecuador Flag of Ecuador
IATA Code: GPS
ICAO Code: SEGS
Coordinates: 0°27′13″S, 90°15′57″W
Destination La Nubia Airport
City: Manizales
Country: Colombia Flag of Colombia
IATA Code: MZL
ICAO Code: SKMZ
Coordinates: 5°1′46″N, 75°27′52″W