How far is Swan River from Fargo, ND?
The distance between Fargo (Hector International Airport) and Swan River (Swan River Airport) is 411 miles / 661 kilometers / 357 nautical miles.
The driving distance from Fargo (FAR) to Swan River (ZJN) is 529 miles / 851 kilometers, and travel time by car is about 10 hours 41 minutes.
Hector International Airport – Swan River Airport
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Distance from Fargo to Swan River
There are several ways to calculate the distance from Fargo to Swan River. Here are two standard methods:
Vincenty's formula (applied above)- 410.532 miles
- 660.688 kilometers
- 356.743 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 410.170 miles
- 660.105 kilometers
- 356.428 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Fargo to Swan River?
The estimated flight time from Hector International Airport to Swan River Airport is 1 hour and 16 minutes.
What is the time difference between Fargo and Swan River?
Flight carbon footprint between Hector International Airport (FAR) and Swan River Airport (ZJN)
On average, flying from Fargo to Swan River generates about 85 kg of CO2 per passenger, and 85 kilograms equals 188 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path and driving directions from Fargo to Swan River
See the map of the shortest flight path between Hector International Airport (FAR) and Swan River Airport (ZJN).
Airport information
Origin | Hector International Airport |
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City: | Fargo, ND |
Country: | United States |
IATA Code: | FAR |
ICAO Code: | KFAR |
Coordinates: | 46°55′14″N, 96°48′56″W |
Destination | Swan River Airport |
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City: | Swan River |
Country: | Canada |
IATA Code: | ZJN |
ICAO Code: | CZJN |
Coordinates: | 52°7′14″N, 101°14′9″W |