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How far is Sandy Lake from Columbus, OH?

The distance between Columbus (John Glenn Columbus International Airport) and Sandy Lake (Sandy Lake Airport) is 1028 miles / 1655 kilometers / 894 nautical miles.

John Glenn Columbus International Airport – Sandy Lake Airport

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1028
Miles
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1655
Kilometers
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894
Nautical miles

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Distance from Columbus to Sandy Lake

There are several ways to calculate the distance from Columbus to Sandy Lake. Here are two standard methods:

Vincenty's formula (applied above)
  • 1028.476 miles
  • 1655.172 kilometers
  • 893.721 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 1028.039 miles
  • 1654.469 kilometers
  • 893.342 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Columbus to Sandy Lake?

The estimated flight time from John Glenn Columbus International Airport to Sandy Lake Airport is 2 hours and 26 minutes.

Flight carbon footprint between John Glenn Columbus International Airport (CMH) and Sandy Lake Airport (ZSJ)

On average, flying from Columbus to Sandy Lake generates about 153 kg of CO2 per passenger, and 153 kilograms equals 336 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Columbus to Sandy Lake

See the map of the shortest flight path between John Glenn Columbus International Airport (CMH) and Sandy Lake Airport (ZSJ).

Airport information

Origin John Glenn Columbus International Airport
City: Columbus, OH
Country: United States Flag of United States
IATA Code: CMH
ICAO Code: KCMH
Coordinates: 39°59′52″N, 82°53′30″W
Destination Sandy Lake Airport
City: Sandy Lake
Country: Canada Flag of Canada
IATA Code: ZSJ
ICAO Code: CZSJ
Coordinates: 53°3′51″N, 93°20′39″W