How far is Sandy Lake from Cleveland, OH?

The distance between Cleveland (Cleveland Hopkins International Airport) and Sandy Lake (Sandy Lake Airport) is 967 miles / 1556 kilometers / 840 nautical miles.

Distance from Cleveland to Sandy Lake

There are several ways to calculate the distance from Cleveland to Sandy Lake. Here are two standard methods:

Vincenty's formula (applied above)

• 967.136 miles
• 1556.455 kilometers
• 840.418 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula

• 966.393 miles
• 1555.259 kilometers
• 839.772 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Cleveland to Sandy Lake?

The estimated flight time from Cleveland Hopkins International Airport to Sandy Lake Airport is 2 hours and 19 minutes.

What is the time difference between Cleveland and Sandy Lake?

The time difference between Cleveland and Sandy Lake is 1 hour. Sandy Lake is 1 hour behind Cleveland.

Flight carbon footprint between Cleveland Hopkins International Airport (CLE) and Sandy Lake Airport (ZSJ)

On average, flying from Cleveland to Sandy Lake generates about 149 kg of CO2 per passenger, and 149 kilograms equals 328 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Cleveland to Sandy Lake

See the map of the shortest flight path between Cleveland Hopkins International Airport (CLE) and Sandy Lake Airport (ZSJ).

Airport information

Origin	Cleveland Hopkins International Airport
City:	Cleveland, OH
Country:	United States
IATA Code:	CLE
ICAO Code:	KCLE
Coordinates:	41°24′42″N, 81°50′59″W

Destination	Sandy Lake Airport
City:	Sandy Lake
Country:	Canada
IATA Code:	ZSJ
ICAO Code:	CZSJ
Coordinates:	53°3′51″N, 93°20′39″W