How far is Sainyabuli from Cleveland, OH?

The distance between Cleveland (Cleveland Hopkins International Airport) and Sainyabuli (Sayaboury Airport) is 8251 miles / 13279 kilometers / 7170 nautical miles.

Distance from Cleveland to Sainyabuli

There are several ways to calculate the distance from Cleveland to Sainyabuli. Here are two standard methods:

Vincenty's formula (applied above)

• 8251.211 miles
• 13279.037 kilometers
• 7170.107 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula

• 8239.734 miles
• 13260.566 kilometers
• 7160.133 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Cleveland to Sainyabuli?

The estimated flight time from Cleveland Hopkins International Airport to Sayaboury Airport is 16 hours and 7 minutes.

What is the time difference between Cleveland and Sainyabuli?

The time difference between Cleveland and Sainyabuli is 12 hours. Sainyabuli is 12 hours ahead of Cleveland.

Flight carbon footprint between Cleveland Hopkins International Airport (CLE) and Sayaboury Airport (ZBY)

On average, flying from Cleveland to Sainyabuli generates about 1 035 kg of CO2 per passenger, and 1 035 kilograms equals 2 282 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Cleveland to Sainyabuli

See the map of the shortest flight path between Cleveland Hopkins International Airport (CLE) and Sayaboury Airport (ZBY).

Airport information

Origin	Cleveland Hopkins International Airport
City:	Cleveland, OH
Country:	United States
IATA Code:	CLE
ICAO Code:	KCLE
Coordinates:	41°24′42″N, 81°50′59″W

Destination	Sayaboury Airport
City:	Sainyabuli
Country:	Laos
IATA Code:	ZBY
ICAO Code:	VLSB
Coordinates:	19°14′36″N, 101°42′33″E