How far is Sandy Lake from Clarksburg, WV?

The distance between Clarksburg (North Central West Virginia Airport) and Sandy Lake (Sandy Lake Airport) is 1136 miles / 1829 kilometers / 987 nautical miles.

Distance from Clarksburg to Sandy Lake

There are several ways to calculate the distance from Clarksburg to Sandy Lake. Here are two standard methods:

Vincenty's formula (applied above)

• 1136.290 miles
• 1828.682 kilometers
• 987.409 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula

• 1135.613 miles
• 1827.592 kilometers
• 986.821 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Clarksburg to Sandy Lake?

The estimated flight time from North Central West Virginia Airport to Sandy Lake Airport is 2 hours and 39 minutes.

What is the time difference between Clarksburg and Sandy Lake?

The time difference between Clarksburg and Sandy Lake is 1 hour. Sandy Lake is 1 hour behind Clarksburg.

Flight carbon footprint between North Central West Virginia Airport (CKB) and Sandy Lake Airport (ZSJ)

On average, flying from Clarksburg to Sandy Lake generates about 159 kg of CO2 per passenger, and 159 kilograms equals 350 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Clarksburg to Sandy Lake

See the map of the shortest flight path between North Central West Virginia Airport (CKB) and Sandy Lake Airport (ZSJ).

Airport information

Origin	North Central West Virginia Airport
City:	Clarksburg, WV
Country:	United States
IATA Code:	CKB
ICAO Code:	KCKB
Coordinates:	39°17′47″N, 80°13′41″W

Destination	Sandy Lake Airport
City:	Sandy Lake
Country:	Canada
IATA Code:	ZSJ
ICAO Code:	CZSJ
Coordinates:	53°3′51″N, 93°20′39″W