How far is Orlando, FL, from Christchurch?
The distance between Christchurch (Christchurch Airport) and Orlando (Orlando Sanford International Airport) is 8328 miles / 13403 kilometers / 7237 nautical miles.
Christchurch Airport – Orlando Sanford International Airport
Search flights
Distance from Christchurch to Orlando
There are several ways to calculate the distance from Christchurch to Orlando. Here are two standard methods:
Vincenty's formula (applied above)- 8328.100 miles
- 13402.778 kilometers
- 7236.921 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 8332.715 miles
- 13410.205 kilometers
- 7240.931 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Christchurch to Orlando?
The estimated flight time from Christchurch Airport to Orlando Sanford International Airport is 16 hours and 16 minutes.
What is the time difference between Christchurch and Orlando?
Flight carbon footprint between Christchurch Airport (CHC) and Orlando Sanford International Airport (SFB)
On average, flying from Christchurch to Orlando generates about 1 047 kg of CO2 per passenger, and 1 047 kilograms equals 2 307 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path from Christchurch to Orlando
See the map of the shortest flight path between Christchurch Airport (CHC) and Orlando Sanford International Airport (SFB).
Airport information
Origin | Christchurch Airport |
---|---|
City: | Christchurch |
Country: | New Zealand |
IATA Code: | CHC |
ICAO Code: | NZCH |
Coordinates: | 43°29′21″S, 172°31′55″E |
Destination | Orlando Sanford International Airport |
---|---|
City: | Orlando, FL |
Country: | United States |
IATA Code: | SFB |
ICAO Code: | KSFB |
Coordinates: | 28°46′39″N, 81°14′15″W |