How far is Sandy Lake from Calicut?
The distance between Calicut (Calicut International Airport) and Sandy Lake (Sandy Lake Airport) is 7965 miles / 12818 kilometers / 6921 nautical miles.
Calicut International Airport – Sandy Lake Airport
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Distance from Calicut to Sandy Lake
There are several ways to calculate the distance from Calicut to Sandy Lake. Here are two standard methods:
Vincenty's formula (applied above)- 7964.867 miles
- 12818.211 kilometers
- 6921.280 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 7955.992 miles
- 12803.928 kilometers
- 6913.568 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Calicut to Sandy Lake?
The estimated flight time from Calicut International Airport to Sandy Lake Airport is 15 hours and 34 minutes.
What is the time difference between Calicut and Sandy Lake?
Flight carbon footprint between Calicut International Airport (CCJ) and Sandy Lake Airport (ZSJ)
On average, flying from Calicut to Sandy Lake generates about 993 kg of CO2 per passenger, and 993 kilograms equals 2 190 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path from Calicut to Sandy Lake
See the map of the shortest flight path between Calicut International Airport (CCJ) and Sandy Lake Airport (ZSJ).
Airport information
| Origin | Calicut International Airport |
|---|---|
| City: | Calicut |
| Country: | India  |
| IATA Code: | CCJ |
| ICAO Code: | VOCL |
| Coordinates: | 11°8′12″N, 75°57′19″E |
| Destination | Sandy Lake Airport |
|---|---|
| City: | Sandy Lake |
| Country: | Canada  |
| IATA Code: | ZSJ |
| ICAO Code: | CZSJ |
| Coordinates: | 53°3′51″N, 93°20′39″W |