How far is Khajuraho from Calicut?
The distance between Calicut (Calicut International Airport) and Khajuraho (Khajuraho Airport) is 976 miles / 1571 kilometers / 848 nautical miles.
The driving distance from Calicut (CCJ) to Khajuraho (HJR) is 1208 miles / 1944 kilometers, and travel time by car is about 24 hours 19 minutes.
Calicut International Airport – Khajuraho Airport
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Distance from Calicut to Khajuraho
There are several ways to calculate the distance from Calicut to Khajuraho. Here are two standard methods:
Vincenty's formula (applied above)- 976.154 miles
- 1570.967 kilometers
- 848.254 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 980.239 miles
- 1577.542 kilometers
- 851.804 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Calicut to Khajuraho?
The estimated flight time from Calicut International Airport to Khajuraho Airport is 2 hours and 20 minutes.
What is the time difference between Calicut and Khajuraho?
Flight carbon footprint between Calicut International Airport (CCJ) and Khajuraho Airport (HJR)
On average, flying from Calicut to Khajuraho generates about 149 kg of CO2 per passenger, and 149 kilograms equals 329 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path and driving directions from Calicut to Khajuraho
See the map of the shortest flight path between Calicut International Airport (CCJ) and Khajuraho Airport (HJR).
Airport information
Origin | Calicut International Airport |
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City: | Calicut |
Country: | India |
IATA Code: | CCJ |
ICAO Code: | VOCL |
Coordinates: | 11°8′12″N, 75°57′19″E |
Destination | Khajuraho Airport |
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City: | Khajuraho |
Country: | India |
IATA Code: | HJR |
ICAO Code: | VAKJ |
Coordinates: | 24°49′1″N, 79°55′6″E |