How far is Sandy Lake from Kralendijk?
The distance between Kralendijk (Flamingo International Airport) and Sandy Lake (Sandy Lake Airport) is 3143 miles / 5058 kilometers / 2731 nautical miles.
Flamingo International Airport – Sandy Lake Airport
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Distance from Kralendijk to Sandy Lake
There are several ways to calculate the distance from Kralendijk to Sandy Lake. Here are two standard methods:
Vincenty's formula (applied above)- 3143.144 miles
- 5058.399 kilometers
- 2731.317 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 3148.238 miles
- 5066.598 kilometers
- 2735.744 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Kralendijk to Sandy Lake?
The estimated flight time from Flamingo International Airport to Sandy Lake Airport is 6 hours and 27 minutes.
What is the time difference between Kralendijk and Sandy Lake?
Flight carbon footprint between Flamingo International Airport (BON) and Sandy Lake Airport (ZSJ)
On average, flying from Kralendijk to Sandy Lake generates about 351 kg of CO2 per passenger, and 351 kilograms equals 775 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path from Kralendijk to Sandy Lake
See the map of the shortest flight path between Flamingo International Airport (BON) and Sandy Lake Airport (ZSJ).
Airport information
| Origin | Flamingo International Airport |
|---|---|
| City: | Kralendijk |
| Country: | Netherlands Antilles  |
| IATA Code: | BON |
| ICAO Code: | TNCB |
| Coordinates: | 12°7′51″N, 68°16′6″W |
| Destination | Sandy Lake Airport |
|---|---|
| City: | Sandy Lake |
| Country: | Canada  |
| IATA Code: | ZSJ |
| ICAO Code: | CZSJ |
| Coordinates: | 53°3′51″N, 93°20′39″W |