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How far is Sandy Lake from Alexandroupolis?

The distance between Alexandroupolis (Alexandroupoli Airport) and Sandy Lake (Sandy Lake Airport) is 5024 miles / 8086 kilometers / 4366 nautical miles.

Alexandroupoli Airport – Sandy Lake Airport

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5024
Miles
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8086
Kilometers
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4366
Nautical miles

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Distance from Alexandroupolis to Sandy Lake

There are several ways to calculate the distance from Alexandroupolis to Sandy Lake. Here are two standard methods:

Vincenty's formula (applied above)
  • 5024.182 miles
  • 8085.638 kilometers
  • 4365.895 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 5010.371 miles
  • 8063.411 kilometers
  • 4353.893 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Alexandroupolis to Sandy Lake?

The estimated flight time from Alexandroupoli Airport to Sandy Lake Airport is 10 hours and 0 minutes.

Flight carbon footprint between Alexandroupoli Airport (AXD) and Sandy Lake Airport (ZSJ)

On average, flying from Alexandroupolis to Sandy Lake generates about 587 kg of CO2 per passenger, and 587 kilograms equals 1 294 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Alexandroupolis to Sandy Lake

See the map of the shortest flight path between Alexandroupoli Airport (AXD) and Sandy Lake Airport (ZSJ).

Airport information

Origin Alexandroupoli Airport
City: Alexandroupolis
Country: Greece Flag of Greece
IATA Code: AXD
ICAO Code: LGAL
Coordinates: 40°51′21″N, 25°57′22″E
Destination Sandy Lake Airport
City: Sandy Lake
Country: Canada Flag of Canada
IATA Code: ZSJ
ICAO Code: CZSJ
Coordinates: 53°3′51″N, 93°20′39″W