How far is San Angelo, TX, from Alexandroupolis?
The distance between Alexandroupolis (Alexandroupoli Airport) and San Angelo (San Angelo Regional Airport) is 6404 miles / 10306 kilometers / 5565 nautical miles.
Alexandroupoli Airport – San Angelo Regional Airport
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Distance from Alexandroupolis to San Angelo
There are several ways to calculate the distance from Alexandroupolis to San Angelo. Here are two standard methods:
Vincenty's formula (applied above)- 6403.547 miles
- 10305.511 kilometers
- 5564.531 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 6390.038 miles
- 10283.770 kilometers
- 5552.792 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Alexandroupolis to San Angelo?
The estimated flight time from Alexandroupoli Airport to San Angelo Regional Airport is 12 hours and 37 minutes.
What is the time difference between Alexandroupolis and San Angelo?
Flight carbon footprint between Alexandroupoli Airport (AXD) and San Angelo Regional Airport (SJT)
On average, flying from Alexandroupolis to San Angelo generates about 772 kg of CO2 per passenger, and 772 kilograms equals 1 701 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path from Alexandroupolis to San Angelo
See the map of the shortest flight path between Alexandroupoli Airport (AXD) and San Angelo Regional Airport (SJT).
Airport information
| Origin | Alexandroupoli Airport |
|---|---|
| City: | Alexandroupolis |
| Country: | Greece  |
| IATA Code: | AXD |
| ICAO Code: | LGAL |
| Coordinates: | 40°51′21″N, 25°57′22″E |
| Destination | San Angelo Regional Airport |
|---|---|
| City: | San Angelo, TX |
| Country: | United States  |
| IATA Code: | SJT |
| ICAO Code: | KSJT |
| Coordinates: | 31°21′27″N, 100°29′45″W |