How far is Khajuraho from Anshan?
The distance between Anshan (Anshan Teng'ao Airport) and Khajuraho (Khajuraho Airport) is 2701 miles / 4347 kilometers / 2347 nautical miles.
The driving distance from Anshan (AOG) to Khajuraho (HJR) is 3646 miles / 5868 kilometers, and travel time by car is about 68 hours 1 minutes.
Anshan Teng'ao Airport – Khajuraho Airport
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Distance from Anshan to Khajuraho
There are several ways to calculate the distance from Anshan to Khajuraho. Here are two standard methods:
Vincenty's formula (applied above)- 2701.196 miles
- 4347.154 kilometers
- 2347.276 nautical miles
Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.
Haversine formula- 2697.716 miles
- 4341.554 kilometers
- 2344.251 nautical miles
The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).
How long does it take to fly from Anshan to Khajuraho?
The estimated flight time from Anshan Teng'ao Airport to Khajuraho Airport is 5 hours and 36 minutes.
What is the time difference between Anshan and Khajuraho?
Flight carbon footprint between Anshan Teng'ao Airport (AOG) and Khajuraho Airport (HJR)
On average, flying from Anshan to Khajuraho generates about 299 kg of CO2 per passenger, and 299 kilograms equals 659 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.
Map of flight path and driving directions from Anshan to Khajuraho
See the map of the shortest flight path between Anshan Teng'ao Airport (AOG) and Khajuraho Airport (HJR).
Airport information
| Origin | Anshan Teng'ao Airport |
|---|---|
| City: | Anshan |
| Country: | China  |
| IATA Code: | AOG |
| ICAO Code: | ZYAS |
| Coordinates: | 41°6′19″N, 122°51′14″E |
| Destination | Khajuraho Airport |
|---|---|
| City: | Khajuraho |
| Country: | India  |
| IATA Code: | HJR |
| ICAO Code: | VAKJ |
| Coordinates: | 24°49′1″N, 79°55′6″E |