How far is Sandy Lake from Alamosa, CO?

The distance between Alamosa (San Luis Valley Regional Airport) and Sandy Lake (Sandy Lake Airport) is 1236 miles / 1989 kilometers / 1074 nautical miles.

Distance from Alamosa to Sandy Lake

There are several ways to calculate the distance from Alamosa to Sandy Lake. Here are two standard methods:

Vincenty's formula (applied above)

• 1236.073 miles
• 1989.266 kilometers
• 1074.118 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula

• 1235.752 miles
• 1988.750 kilometers
• 1073.839 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Alamosa to Sandy Lake?

The estimated flight time from San Luis Valley Regional Airport to Sandy Lake Airport is 2 hours and 50 minutes.

What is the time difference between Alamosa and Sandy Lake?

The time difference between Alamosa and Sandy Lake is 1 hour. Sandy Lake is 1 hour ahead of Alamosa.

Flight carbon footprint between San Luis Valley Regional Airport (ALS) and Sandy Lake Airport (ZSJ)

On average, flying from Alamosa to Sandy Lake generates about 163 kg of CO2 per passenger, and 163 kilograms equals 359 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Alamosa to Sandy Lake

See the map of the shortest flight path between San Luis Valley Regional Airport (ALS) and Sandy Lake Airport (ZSJ).

Airport information

Origin	San Luis Valley Regional Airport
City:	Alamosa, CO
Country:	United States
IATA Code:	ALS
ICAO Code:	KALS
Coordinates:	37°26′5″N, 105°52′1″W

Destination	Sandy Lake Airport
City:	Sandy Lake
Country:	Canada
IATA Code:	ZSJ
ICAO Code:	CZSJ
Coordinates:	53°3′51″N, 93°20′39″W